Question

perimeter of a rectangle

Answer 1

You're posting a lot of questions? Is your book and/or teacher really bad?

Answer 2

ummmmm extremly

Answer 3

I understand with the story problem thing. Never liked 'em.

Answer 4

Try getting a new teacher! :D

Answer 5

tell me about it. i'm half way through the class for my BA

Answer 6

this is the last class i need

Answer 7

Someone helllp!

Answer 8

yea tell me about it

Answer 9

2(L + W ) =88

2( (12+L) + 2W) = 152

Answer 10

Two equations.

Answer 11

Oh damn, that's a good answer! If I could give you another medal I would :-)

Answer 12

Thankyou! ^_^

Answer 13

its a shame none of those are my answers lol

Answer 14

Confession: from elementary school all the way up through college, applied problems have been a thorn in my side.

You've gotta get a really good teacher/tutor and also go through tons of these things until you get them. (but look who's talking, the one who still can't do them!)

Answer 15

ha ha

Answer 16

p=2(l+b)......1
p'=2(l'+b') ......2
perimeter of the rectangle is 88 so p=88
change in width is double the original which is b'=2b
change in length is increased by 12 m which is l'=l+12
change in perimeter or p'=152
now the question is find the l=?
by putting values in eq: 1 we get
88=2(l+b)
88=2l+2b.....3
now putting values in equation 2 we get
152=2{(l+12)+(2b)}
76=l+12+2b
64=l+2b......4
subtracting eq: 4 from 3
88=2l+2b
64=l+2b
we get
24=l hence i think this is the final result hope this help you letting me now that is is right or wrong

Answer 17

2 ( w + L ) = 88 --> w + L = 44
2 [ 2w + L + 12) = 152 -> 2w + L +12 = 76
-> 2w + L = 64
Eliminate:
->w = 20 m => L = 24 m