Mathematics
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OpenStudy (saifoo.khan):
Find the area.
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OpenStudy (saifoo.khan):
OpenStudy (bahrom7893):
area of that shaded region?
OpenStudy (saifoo.khan):
Yes
OpenStudy (bahrom7893):
Hmm they didn't give the angle did they..
OpenStudy (saifoo.khan):
i found the angle, check the attachement now, i updated.
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OpenStudy (bahrom7893):
Hm Area of that sector = (1/2)r^2(theta) = (1/2)*25*1.85 = 23.125
OpenStudy (bahrom7893):
Do they give the perimeter or any other info for the rectangle?
OpenStudy (saifoo.khan):
No. this is all i have.
in the first part they asked for angle. ANd in second part SR
OpenStudy (bahrom7893):
Wait a sec.. what's SR?
OpenStudy (saifoo.khan):
SR = Shaded Region.
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OpenStudy (bahrom7893):
ohh ok..
OpenStudy (saifoo.khan):
OpenStudy (bahrom7893):
Ohh that's it then
OpenStudy (bahrom7893):
wait a second.. that's not it.. hmmm lol tricky
OpenStudy (bahrom7893):
Okay find the area of the rectangle, which is 16. Now the area of the two right triangles.
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OpenStudy (saifoo.khan):
Now we can find the area of triangle - area of 2 |dw:1331361361149:dw|
OpenStudy (bahrom7893):
Area of one of the triangles is (1/2)*3*4 = 6, and there are two of them, so the total area is 12.
OpenStudy (bahrom7893):
And the total area of the weird looking figure is 16+12=28
OpenStudy (saifoo.khan):
\[\frac12 (2)(4) - \frac12(0.925 - \sin (0.925))\]
OpenStudy (bahrom7893):
Now subtract the area of the sector:
28 - 23.125, and divide by 2.
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OpenStudy (bahrom7893):
SR = 2.4375
OpenStudy (anonymous):
2.4375 sq cm
OpenStudy (saifoo.khan):
That's correct.
OpenStudy (ash2326):
|dw:1331361196474:dw|
Required Area= (Area of the figure- Area of sector)/2
=(area of triangle+ area of rectangle- 1.85 *r^2)/2
OpenStudy (saifoo.khan):
2.44cm^2
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OpenStudy (bahrom7893):
Getting the area of the triangles is easy. one half base times height.