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Mathematics 21 Online
OpenStudy (saifoo.khan):

Find the area.

OpenStudy (saifoo.khan):

OpenStudy (bahrom7893):

area of that shaded region?

OpenStudy (saifoo.khan):

Yes

OpenStudy (bahrom7893):

Hmm they didn't give the angle did they..

OpenStudy (saifoo.khan):

i found the angle, check the attachement now, i updated.

OpenStudy (bahrom7893):

Hm Area of that sector = (1/2)r^2(theta) = (1/2)*25*1.85 = 23.125

OpenStudy (bahrom7893):

Do they give the perimeter or any other info for the rectangle?

OpenStudy (saifoo.khan):

No. this is all i have. in the first part they asked for angle. ANd in second part SR

OpenStudy (bahrom7893):

Wait a sec.. what's SR?

OpenStudy (saifoo.khan):

SR = Shaded Region.

OpenStudy (bahrom7893):

ohh ok..

OpenStudy (saifoo.khan):

OpenStudy (bahrom7893):

Ohh that's it then

OpenStudy (bahrom7893):

wait a second.. that's not it.. hmmm lol tricky

OpenStudy (bahrom7893):

Okay find the area of the rectangle, which is 16. Now the area of the two right triangles.

OpenStudy (saifoo.khan):

Now we can find the area of triangle - area of 2 |dw:1331361361149:dw|

OpenStudy (bahrom7893):

Area of one of the triangles is (1/2)*3*4 = 6, and there are two of them, so the total area is 12.

OpenStudy (bahrom7893):

And the total area of the weird looking figure is 16+12=28

OpenStudy (saifoo.khan):

\[\frac12 (2)(4) - \frac12(0.925 - \sin (0.925))\]

OpenStudy (bahrom7893):

Now subtract the area of the sector: 28 - 23.125, and divide by 2.

OpenStudy (bahrom7893):

SR = 2.4375

OpenStudy (anonymous):

2.4375 sq cm

OpenStudy (saifoo.khan):

That's correct.

OpenStudy (ash2326):

|dw:1331361196474:dw| Required Area= (Area of the figure- Area of sector)/2 =(area of triangle+ area of rectangle- 1.85 *r^2)/2

OpenStudy (saifoo.khan):

2.44cm^2

OpenStudy (bahrom7893):

Getting the area of the triangles is easy. one half base times height.

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