Question

at the given point fine the slope of the curve the line that is tangent to the curve or the line that is normal to the curve.

x^3y^3=8 tangent at (2,1)

Answer 1

x^3 y^3 = 8
xy = 2
y = 2/x
y' = -2/x^2
y' (2) = -2 / 4 = -1/2
Ytangent = (-1/2)(x - 2) + 1