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Differentiate (t^2 + 2)/(t^4 - 3t^2 + 1)
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use quotient rule
Why are you reposting this?
by way of the quotient rule i got [2t(-t^4 - 7t^2 + 7)]/[(t^4 - 3t^3 + 1)^2], which is incorrect apparently... close but no cigar. any ideas?
idk i thought everyone had quit out on the other one
double teaming
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(t^2-2)T^4-t^2-1)/(t^2-t-1)(t^2+t-1)
what.
http://tutorial.math.lamar.edu/Classes/CalcI/ProductQuotientRule_files/eq0010M.gif
= -2t ( t^4 + 4t^2 - 7) / ( t^4 - 3t^2 + 1)
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\[y'=\frac{-2t(t^4+4t^2-7)}{(t^4-3t^2+1)^2}\]
I miss typed the square under the denominator!
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