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OpenStudy (anonymous):
Differentiate f(x) = x / (x + c/x)
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OpenStudy (anonymous):
See if this works for you.\[f(x) = x / (x + c/x)=x^2/(x^2+c)=(x^2+c-c)/(x^2+c)=1-c/(x^2+c)\]\[f'(x)=-2cx \ln(x^2+c)\]
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