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Mathematics 14 Online
OpenStudy (anonymous):

Differentiate f(x) = x / (x + c/x)

OpenStudy (anonymous):

See if this works for you.\[f(x) = x / (x + c/x)=x^2/(x^2+c)=(x^2+c-c)/(x^2+c)=1-c/(x^2+c)\]\[f'(x)=-2cx \ln(x^2+c)\]

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