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Differentiate f(x) = x / (x + c/x)
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\[f(x)=\frac{x^2}{x^2+c}\]
f(x)=x^2/c+x^2 c/c+2x^2f(x)=1
\[\frac{2x(x^2+c)-x^2(2x)}{(x^2+c)^2}\]
use the quotient rule u = x^2 du/dx = 2x v = x^2 + c dv/dx = 2x dy/dx = {(x^2 +c)2x - (x^2)2x}/(x^2 + c)^2 you can simplify it
\[\frac{2xc}{(x^2+c)^2}\]
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