Question

if Sec^-1 5x = y - csc^-1 5x, then d^2 y/dx^2 is equal to
A. 5
b. 5x
c. -5
d. 0

Answer 1

y=csc^-1(5 x)+sec^-1(5 x)
dy/dx =0
d^2y/dx^2=0

d

Answer 2

i thought its 5 because of d^2 hehe thanks sam

Answer 3

arccsc(5x)+arcsec(5x)

derivative of arccsc(5x)
d/dx arccsc(5x)=-(1)/(x√(25x^(2)+1))

derivative of arcsec(5x)
d/dx arcsec(5x)=(1)/(x√(25x^(2)+1))



d/dx of arccsc(5x)+arcsec(5x)=-1/(x√(25x^(2)+1)) + 1/(x√(25x^(2)+1))

Combine all similar expressions.
0

Answer 4

thanks sam it help me

Answer 5

im just confuse of d^2 y /dx^2 i thought its like this 5^2y/ 5x^2 but u solve it now i get it