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Mathematics 13 Online
OpenStudy (anonymous):

p^2 - xp = X^2 what is dp/dx

OpenStudy (mathmagician):

dp/dx(p^2-xp-x^2)=-(p+2x)

OpenStudy (anonymous):

\[dp/dx = (2x+p)/(2p-x)\]

OpenStudy (anonymous):

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