Question

Darren designed this triangular shaped entrance, ABC, to a mall.

Which expression can be used to find the distance between the points B and C of the entrance?
A. 15/cot 65 degrees +15/cot 25 degrees
B.15/cot 65 degrees + 15/sec 25 degrees
C.15 (cot 65° + sec 25°)
D. 15(cot 65° + cot 25°)

Answer 1

i was guessing d

Answer 2

\[\cot 65=\frac{BD}{15}\]
\[BD=15\cot65\]
\[\cot 25=\frac{DC}{15}\]
\[DC=15\cot 25\]
\[BC=BD+DC=15\cot 65+15\cot25=15(\cot 65+\cot 25)\]

Answer 3

yea thanks :)

Answer 4

yw

Answer 5

D. 15(cot 65° + cot 25°)