when y = ab Tan^-1 (acotx)/b, then y' is equal to?
a. (a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
b. (-a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
c. (a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)
d. (-a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)

Question

when y = ab Tan^-1 (acotx)/b, then y' is equal to?
a. (a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
b. (-a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
c. (a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)
d. (-a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)

matt101 · Answer

B (assuming a and b are constants)

I can try to write out the solution here if you need it, but it'll take a while haha...
Alternatively, Wolfram Alpha :P

anonymous · Answer

i getting all the answer when i formulate it

anonymous · Answer

when i put it on alpha i get all the answer correct huhu