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OpenStudy (anonymous):
physics question on motion ...see attachment
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OpenStudy (anonymous):
OpenStudy (anonymous):
come on guys
OpenStudy (anonymous):
4 people viewing and no-one answering :p
OpenStudy (anonymous):
w8 dude..
OpenStudy (anonymous):
ko everyone hahahha
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sam (.sam.):
Vy = 10 -2t Vx = 8 + 4t Sy = y-coordinate Sy = integral of 10-2t = 10t - t^2 + c dSy/dt = 10 - 2t = 0 for maximum this is given from the first equation t = 5 Vy = 0 Vx = 8 + 28 Velocity = 28 m/s in direction x
OpenStudy (anonymous):
hmm the book says the answer is (32 m/s)î
OpenStudy (anonymous):
sorry will be back later
sam (.sam.):
Thats in the x direction
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