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Mathematics 9 Online
OpenStudy (anonymous):

physics question on motion ...see attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

come on guys

OpenStudy (anonymous):

4 people viewing and no-one answering :p

OpenStudy (anonymous):

w8 dude..

OpenStudy (anonymous):

ko everyone hahahha

sam (.sam.):

Vy = 10 -2t Vx = 8 + 4t Sy = y-coordinate Sy = integral of 10-2t = 10t - t^2 + c dSy/dt = 10 - 2t = 0 for maximum this is given from the first equation t = 5 Vy = 0 Vx = 8 + 28 Velocity = 28 m/s in direction x

OpenStudy (anonymous):

hmm the book says the answer is (32 m/s)î

OpenStudy (anonymous):

sorry will be back later

sam (.sam.):

Thats in the x direction

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