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find y'(1) if y = tan^-1 x + Sec^-1 sqrt(1+x^2) a. 0 b.2 c.1 d.3
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1
PUT TAN X =Z
YOU WILL GET Y = 2 * TAN INVERSE OF X
what is z?
Z IS ANY ANGLE. IF U PUT X=Z U WILL GET Y= Z+Z BUT Z= TAN^-1 (X) HENCE Y=2* TAN^-1(X) Y'=2 * 1/(1+X^2) AND Y(1)=1
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