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Mathematics
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6x/8y^3 ÷ (2x^2)^3/9x^4 =
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(im checking my answers)
I got 54x^11/y^3 seems wrong but I'm not sure if I misinterpreted the inital question.
i did this: 6x/8y^3 ÷ (2x^2)^3/9x^4 = 2x/2y^3 ÷ x^6/3y^4 = 2x/2y^3 * 3y/x^5 = 6xy/2x^5
and also : (-x^2)^3/4z ÷ 3x/8z^2 =
|dw:1331617947820:dw|
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