Question

given that g(x)=2-3x and h(x)=mx+n, where m and n are constant.

find
a) g^-1 (x)

b) g^2 (x)

c) the value of m and of n if gh(x) = -x-1

Answer 1

The first one is obtained by getting the reciprocal of g(x).(1/(2-3x)
Square g(x) to get the second one.
Put x = mx+n in g(x)
g(h(x))=2-3(mx+n)=-x-1
Maybe I interpreted the question incorrectly, but you cannot solve both for m and n. Is there any other information given?

Answer 2

no~