Question

(2t^2-8t+6)/(t-3)

Answer 1

Numertor : 2t^2 - 6t - 2t + 6
2t(t -3) -2 (t-3)
(2t-2)(t-3)
Therefore on dividint with t - 3,
2t-2 remains

Answer 2

I assumed you want a simplification.

Answer 3

2t^2-6t-2t+12
2t(t-3)-2(t-3)
(2t-2)(t-3)
hence cancel (t-3)
2(t-1)

Answer 4

Its 2t^2-8t+6

Answer 5

yah!!! mistyped sorry