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Use the quadratic formula to solve x2 - 2x - 3 = 0
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\[ x^2 - 2x - 3= (x+1)(x-3) \]
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D = b^2 - 4ac D = 4 - 4*(-3)*1 D = 16 Therefore sqrtD = 4 Putting in formula, = -b +/- (sqrt D)/2a = (2 (+/-) 4 )/ 2 = 1+/- 2 = 3 or -1
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