Question

Use the quadratic formula to solve x2 - 2x - 3 = 0

Answer 1

\[ x^2 - 2x - 3= (x+1)(x-3) \]

Answer 2

thank you

Answer 3

D = b^2 - 4ac
D = 4 - 4*(-3)*1
D = 16
Therefore sqrtD = 4
Putting in formula,
= -b +/- (sqrt D)/2a
= (2 (+/-) 4 )/ 2
= 1+/- 2
= 3 or -1