Question

In circle A shown below, BD is a diameter and the measure of CB is 36°.
What is the measure of ∡DBC?

Answer 1

to prove it join AC

then angle CAB = 36 angle at the centre subtended by arc CB

angle CDB = 18 ( angle at the centre is double the angle at the circumference standing on the same arc CB)

Angle BCD = 90 ( angle in a semi circle)

therefore angle DBC = 72 ( angle sum of a triangle)

Answer 2

Oh, I was using the wrong equation. I kept getting 36. Thank you!