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Lines CD and DE are tangent to circle A shown below. If CE is 112°, what is the measure of ∡CDE?
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The angle is 1/2 the difference of the intercepted arcs.
Join AE and AE Angle DCA = angle AED (both 90, tangent and radius intercect at right angles) Angle CAE = 112 Angle at the centre subtended by the arc CE Angle CDE = 68 angle sum of the quadrilateral DCAE
So 1/2(248-112)=1/2(136)=68
Thank you both. Geometry is really confusing for me, I didnt even know how to write this problem out!
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