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OpenStudy (anonymous):

Factor: n^2+4n-21

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OpenStudy (anonymous):

quadratic is (-4 +-sqrt(100))/2

OpenStudy (cwrw238):

you need two numbers whose product is -21 and sum = + 4 then insert them into the blank spaces: (n )(n )

OpenStudy (anonymous):

(n+7)(n-3) gives n=-7 and n=+3

OpenStudy (anonymous):

that would be correct

OpenStudy (anonymous):

MCronin, your way involves less trial and error ;) I can appreciate that!

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OpenStudy (cwrw238):

the question asked to factor the function so answer is (x+7)(x-3)

OpenStudy (anonymous):

True, but the quadratic formula is useful in finding those factors as well. One method is not more "right" than the other.

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