Question

Circle A has an equation of x2 + (y + 3)2 = 16. Where is the center of the circle located?
Answer

Answer 1

assuming the equation is x^2 + (y+3)^2 = 16, then your center is located at (0,-3)

Answer 2

so it would be on the on the y-axis? yes? no?

Answer 3

yes