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OpenStudy (anonymous):
Circle A has an equation of x2 + (y + 3)2 = 16. Where is the center of the circle located? Answer
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OpenStudy (anonymous):
assuming the equation is x^2 + (y+3)^2 = 16, then your center is located at (0,-3)
OpenStudy (anonymous):
so it would be on the on the y-axis? yes? no?
OpenStudy (anonymous):
yes
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