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Let f(x) = 2x+3 and g(x) = -x^2 + 5 find ( f of f)(x)
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ff(x) f(f(x)) f(2x+3) 2(2x+3)+3
its just like substituting
Looks like they're giving g(x) to throw you off!
28 was the rigth answer (:
yay!
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@Lib Libs Does it make sense to plug the eqn of f(x) into f(x)?
Yes. It does. It's just asking for f of f
Wait. ; - ; i got confused.
f(x) = 2x+3) f(f(x)) = f(2x+3) f(2x+3) = 2(2x+3) +3 So you're just plugging your function into itself.
4x + 3 2x + 3 4x + 9 4x2 + 12x + 9 It would be 2x +3?
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Not quite... f(2x+3) =4x +6 +3 =4x+9
Darnit D< I will get it right.
I got two right today :/
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