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OpenStudy (anonymous):
How many liters of 18.5 molar HCl stock solution will be needed to make 25.0 liters of 1.5 molar HCl solution? Show the work used to solve this problem.
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OpenStudy (rogue):
Didn't Mert answer this in the math section? =P \[M_1 V_1 = M_2 V_2\]\[18.5 M \times V_1 = 1.5 M \times 25.0 L\]\[V_1 = \frac {37.5 mol HCl}{18.5M} = 2.03 L\]
OpenStudy (anonymous):
lol no that was a different one haha thank you(:
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