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In △JKL, solve for x. (Picture attached) Answer 17.32 38.16 66.73 74.89
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What picture?
\[\tan \theta = \frac{opp}{adj}\]
\[\tan 27 = \frac{34}{x}\]
\[x = \frac{34}{\tan 27}\]
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\[x \approx 66.73\]
so the answer is 66.73 @pineapple31
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