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Mathematics 22 Online
OpenStudy (anonymous):

In △JKL, solve for x. (Picture attached) Answer 17.32 38.16 66.73 74.89

hero (hero):

What picture?

OpenStudy (anonymous):

hero (hero):

\[\tan \theta = \frac{opp}{adj}\]

hero (hero):

\[\tan 27 = \frac{34}{x}\]

hero (hero):

\[x = \frac{34}{\tan 27}\]

hero (hero):

\[x \approx 66.73\]

OpenStudy (anonymous):

so the answer is 66.73 @pineapple31

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