find y' of sin^-1 (y/x) = 1 - cos^-1 (x/y)

a. -(x/y)

b.-(y/x)

c. y/x

d.x/y

Question

find y' of sin^-1 (y/x) = 1 - cos^-1 (x/y)

a. -(x/y)

b.-(y/x)

c. y/x

d.x/y

anonymous · Answer

y' means differentiation?

anonymous · Answer

yes

anonymous · Answer

I am assuming with respect to x. Okay so where are you stuck?

anonymous · Answer

letter A is false letter B is false i think its letter C   or letter E = error

anonymous · Answer

Do you just need the answer?

anonymous · Answer

yes my prof always do this i just forgot it i need to memorize the question

anonymous · Answer

Memorization is not a good idea. Anyways, for this problem you will just need to use chain rule and implicit differentiation. Let me know if you need help in solving the actual problem.

anonymous · Answer

w8 i give the other question of my prof its similar it has a answer

anonymous · Answer

I think I don't need that :)

anonymous · Answer

if sin (y/x) = x/y' then y' is   a. - (x/y) b. -(y/x)  c. y/x   d. x/y

anonymous · Answer

he answer c

anonymous · Answer

i look to the question today and its like the same