find y' of sin^-1 (y/x) = 1 - cos^-1 (x/y)
a. -(x/y)
b.-(y/x)
c. y/x
d.x/y
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OpenStudy (anonymous):
y' means differentiation?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
I am assuming with respect to x. Okay so where are you stuck?
OpenStudy (anonymous):
letter A is false letter B is false i think its letter C or letter E = error
OpenStudy (anonymous):
Do you just need the answer?
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OpenStudy (anonymous):
yes my prof always do this i just forgot it i need to memorize the question
OpenStudy (anonymous):
Memorization is not a good idea. Anyways, for this problem you will just need to use chain rule and implicit differentiation. Let me know if you need help in solving the actual problem.
OpenStudy (anonymous):
w8 i give the other question of my prof its similar it has a answer
OpenStudy (anonymous):
I think I don't need that :)
OpenStudy (anonymous):
if sin (y/x) = x/y' then y' is a. - (x/y) b. -(y/x) c. y/x d. x/y
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OpenStudy (anonymous):
he answer c
OpenStudy (anonymous):
i look to the question today and its like the same