Question

solve for x in the proportion (3x)/(3x-36)= -1/x

Answer 1

cross multiply

Answer 2

ik but i can't find the answer plz help

Answer 3

@precal help

Answer 4

@nicole1217
sorry I have been busy, let me help you

Answer 5

\[\frac{3x}{3x-36}=\frac{-1}{x}\]
cross multiply
\[3x^2=-1(3x-36)\]
\[3x^2=-3x+36\]
\[3x^2+3x-36=0\]

Answer 6

\[3(x^2+x-12)=0\]
3(x+4)(x-3)=0
x=-4 x=3