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solve for x in the proportion (3x)/(3x-36)= -1/x
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cross multiply
ik but i can't find the answer plz help
@precal help
@nicole1217 sorry I have been busy, let me help you
\[\frac{3x}{3x-36}=\frac{-1}{x}\] cross multiply \[3x^2=-1(3x-36)\] \[3x^2=-3x+36\] \[3x^2+3x-36=0\]
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\[3(x^2+x-12)=0\] 3(x+4)(x-3)=0 x=-4 x=3
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