Question

in derivatives of trigonometric functions ..y=tan(sinx)

Answer 1

do u just want to find the derivative?

Answer 2

listen u gotta respond. I can't guess what the question was asking.

Answer 3

..yes, the derivative ..

Answer 4

chain rule...
y = tan(sinx)
y' = [tan(sinx)]' * [sinx]'
= sec^2(sinx) * cosx
= cosx * sec^2(sinx)