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OpenStudy (anonymous):
in derivatives of trigonometric functions ..y=tan(sinx)
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OpenStudy (bahrom7893):
do u just want to find the derivative?
OpenStudy (bahrom7893):
listen u gotta respond. I can't guess what the question was asking.
OpenStudy (anonymous):
..yes, the derivative ..
OpenStudy (anonymous):
chain rule... y = tan(sinx) y' = [tan(sinx)]' * [sinx]' = sec^2(sinx) * cosx = cosx * sec^2(sinx)
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