What are the critical points for y' = 8x/ (x^2+4)^2

Question

anonymous · Answer

x = 0
-> f (0) = ..   (plug into original equation to find y value of critical point)

anonymous · Answer

I know that too
but I only got x=0 as the critical number
so juz wondering if there are others other than 0

anonymous · Answer

Where's your f(x)?

anonymous · Answer

y = x^2 / (x^2 + 4)

for this one, i also only got 0..

anonymous · Answer

so then the whole function will have no local min or max, or cusp or vertical tangent?

anonymous · Answer

Since you plug f(0) = 0 ==> critical point (0,0)

anonymous · Answer

Yep, a lot of rational graph just increasing, decreasing!

anonymous · Answer

there's nothing wrong with it!

anonymous · Answer

ohh ok thanks! 
oh so my part 3 asks to find 2second derivative and cocavity
so basically i can skip that since there is no concave points?

anonymous · Answer

You just lucky at this one! however try to practice all types so you can be ready for your tests!

anonymous · Answer

thanks

yea i have alot others to do haha

anonymous · Answer

post and make sure type it clearly, make it easy for us to solve it precisely :)