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Simplify the expression using the properties of exponents: (3a/b-1)-2
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is that \[({3a\over b-1})^{-2}\]?
Yes. Sorry, I don't know how to enter exponents in here.
i would wright x to the power y as x^y
Ok. Thank you.
\[({3a \over b-1})^{-2}=({b-1 \over 3a})^2={(b-1)^2 \over (3a)^2}\] \[={b^2-2b+1\over 9a^2}\]
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perhaps this is more simple \[{(b-1)^{2} \over 9a^2}\]
The computer doesn't like that answer. Ummm...ok.
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