Question

Solve:
1/9=27^2x-2
dont get it! pls help!...

Answer 1

\[\frac{1}{9} = 3^{-2}\]
\[27 = 3^{3}\]
\[\rightarrow 3^{-2} = 3^{3(2x-2)}\]
set exponents equal
\[3(2x-2) = -2\]
solve for x

Answer 2

thank you

Answer 3

welcome :)
btw you should get x=2/3

Answer 4

yes tats wat i got