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what is (x+2)^8 ?
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Binomial expansion
can you give the answer ?
When n=8 , r=0 \[^{n}C _{r}(a)^{r}(b)^{8}=\] \[^{n}C _{r+1}(a)^{r}(b)^{7}=\] \[^{n}C _{r+2}(a)^{r}(b)^{6}=\] \[^{n}C _{r+3}(a)^{r}(b)^{5}=\] Work your way down untill \[^{8}C _{8}(a)^{8}(b)^{0}=\]
[(x+4y)^8]
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