Question

Math Analysis: Solve for 0° 14 years ago

Answer 1

6sin^2x=7-5cosx

change the left side to 6*(1-cos^2(x)) so your equation now is
6*(1-cos^2(x)) = 7-5cosx
6 - 6*cos^2(x) = 7-5cosx
0 = 6*cos^2(x) -5*cosx +1

now you can treat this like a quadratic equation...

Answer 2

6 - 6cos^2 x = 7 - 5cosx
6cos^2x - 5cosx + 1 = 0
(2cosx - 1)(3cosx-1) = 0

cosx= 1/2 and cosx= 1/3

Answer 3

now solve akshat4 equations...

Answer 4

okay, thx everybdoy! :D