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\[(x+3)^2(x-5)^2\]
\[f(x)=(x+3)^2(x-5)^2\]
To verify 0s of x: \[(x+3)^2(x-5)^2=0\] \[(x+3)^2=0\] \[(x-5)^2=0\]
how would you verify the zeros of f(x)?
\[(x+3)(x+3)=0\] \[(x-5)(x-5)=0\] So now you have 4 equations: \[x+3=0\] \[x+3=0\] \[x-5=0\] \[x-5=0\]
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Solve them to get the solutions: \[x=-3\] \[x=-3\] \[x=5\] \[x=5\] See two repeated roots, one is -3, the other one is 5
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