Question

I need help with factoring!
x^6-y^6?

Answer 1

difference of squares

--> (x^3 +y^3)(x^3 -y^3)

then 2nd factor is a difference of cubes

-->(x^3 +y^3)(x-y)(x^2+xy+y^2)

Answer 2

(x^3)^2 - (y^3)2

Answer 3

Hey, you can factorise x^3 + y^3.

Answer 4

x^3 + y^3 = (x - y)(x^2 + xy + y^2)

Answer 5

Thank you so much!

Answer 6

yw

Answer 7

oh yeah i missed that :)
so final answer
--> (x-y)(x+y)(x^2+xy+y^2)(x^2-xy+y^2)