Question

factor a^3^y+1? please!

Answer 1

is that written correctly?
\[\large a^{3^{y}} +1\]

Answer 2

yes

Answer 3

if it is iguess its a sum of cubes
\[\large a^{3^{y}} = (a^{3^{y-1}})^{3}\]
\[\large \rightarrow (a^{3^{y-1}} +1)(a^{2*3^{y-1}}- a^{3^{y-1}}+1)\]

Answer 4

Okay, thanks. It just says factoring special products sooo I don't really know. But I'll give this a go! thanks so much!