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Mathematics 15 Online
OpenStudy (anonymous):

Need help with how to go from: n(1/((2^n)(n!))((2n)!/(n!)) to: n(2n/(2n^2))(1/((2^(n-1))(n-1)!)((2n-1)!/(n-1)!)((2n-1)!/((2^(n-1))[(n-1)!]^2)

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