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(y^2-1)(y^2+1)
as (a^2 -B^2)=(a-b)(a+b)
y^4-1 = (y^2-1)(y^2+1) = (y-1)(y+1)(y^2+1)
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can anyone explain please?
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i did so???
y^4-1 = (y^2)^2 - 1^2 use the formula a^2 -B^2=(a-b)(a+b) so you get (y^2-1)(y^2+1) then use the formula again for (y^2-1) so the final answer would be (y-1)(y+1)(y^2+1)
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