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Mathematics 6 Online
OpenStudy (anonymous):

Given the triangle below, what is sec∡B?

OpenStudy (anonymous):

OpenStudy (anonymous):

A

OpenStudy (anonymous):

B

OpenStudy (anonymous):

C

OpenStudy (anonymous):

D

OpenStudy (dumbcow):

C

OpenStudy (anonymous):

you serious?

OpenStudy (dumbcow):

umm yeah why wouldn't i be sec = 1/cos cos = sqrt(1-sin^2) = sqrt(1-(4/7)^2) = sqrt(1-16/49) = sqrt(33)/7 --> sec = 7/sqrt(33) = 7sqrt(33)/33

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