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f(x)=x^2-10
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and what is the question?
are you adding more to the directions?
Graphing it! vertex, axis of symetry, and a few points needed. Sorry thanks for your help!
standard form is ax^2 + bX + c
vertex is -B/2a note you do not have a x term - so it is 0 for B
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oops I meant that was the axis of symmetry
for the vertx - plug in x = axis of symmetry and solve for Y (x,Y) is your vertex
for ease of graphing also identify the y-intercept - which is (0,C)
let me know if you have other questions but i think you should be able to determine everything you need from that information
so the vertex is (0,-10) axis of symetry is x=0
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agreed
Thank you so so much!!!
anytime
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