Question

solve for X
5x^2+10x-495=0

Answer 1

Start by factoring the expression:
\[5(x ^{2}+2x-99)=0\] Then divide out the five to get\[(x ^{2}+2x-99)=0\] then you can factor again to get \[(x+11)(x-9)=0\] you then know that x+11=0 and that x-9 = 0 so you can get your solutions to x = -11 and x=9