Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

any help to find b?

OpenStudy (anonymous):

@Unam your post?

OpenStudy (anonymous):

Sorry here ....

OpenStudy (anonymous):

OpenStudy (anonymous):

So HOW to find TANGENT LINE?

OpenStudy (anonymous):

WHAT's its FORM?

OpenStudy (anonymous):

Yeah sorry ma bad...I mean all of them... if u could explain it like mathg8 did today, like step by step....

OpenStudy (anonymous):

This is a derivative question I guess

OpenStudy (anonymous):

Wow, so apply what math showed you, however considering TANGENT AS VELOCITY :)

OpenStudy (anonymous):

Great guess :)

OpenStudy (anonymous):

that's what i'm bad at...I just don't get the whole thing...I wish mathg8 is still around to sho it without having to go through verbally conversation... :)

OpenStudy (anonymous):

I wish math here, too. He's clever!

OpenStudy (anonymous):

Anyway, here's the concept!

OpenStudy (anonymous):

VELOCITY, TANGENT, .. are application of DERIVATIVE!

OpenStudy (anonymous):

Can you find tangent line now?

OpenStudy (anonymous):

Do you know the SLOPE y intercept form?

OpenStudy (anonymous):

@Unam can you give it a try?

OpenStudy (anonymous):

thanks C ...what can I do ?

OpenStudy (anonymous):

@unam your savor, here he comes :P

OpenStudy (anonymous):

Tangent line equation!

OpenStudy (anonymous):

LOL

OpenStudy (anonymous):

I told Unam that they're just the same derivative, but he insist on "I wish math here :P"

OpenStudy (anonymous):

@ch haha...sorry i'm trying

OpenStudy (anonymous):

here's what i got so far f'(-4) = 12(-4)^2

OpenStudy (anonymous):

f(x) = 4x^3

OpenStudy (anonymous):

SO what i got is for part a and b but i'm trying to get c :)

OpenStudy (anonymous):

then what you do next, pretending math show you how to find velocity?

OpenStudy (anonymous):

I forgot..short memory

OpenStudy (anonymous):

|dw:1331781141828:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!