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Mathematics 8 Online
OpenStudy (anonymous):

25^(x+2)-125

OpenStudy (mani_jha):

What do you have to do with the expression? What's the question?

OpenStudy (anonymous):

Which of the following is the solution to the equation 25^(z + 2) = 125 ? z = 5.5 z = 3.5 z = –2.5 z = –0.5

OpenStudy (anonymous):

You want to solve \(25^{x+2}-125=0\) I assume?

OpenStudy (anonymous):

yes

OpenStudy (mani_jha):

Yes, AnwarA, that is probably what is being asked for. \[25^{x+2}=5^{2(x+2)}\] 125=5^3 Now, can you solve it?

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