Question

I am forgetting something
.0386=x/12, 10=x^-1 or 12=x^2
how do I find x?

Answer 1

on the first one, .0386 will be multiplied by 12.

so that, (.0386)*12=x

Answer 2

on the second one,

10=1\x

x=1\10

Answer 3

on the third one,

find the square rt of both sides..

that makes,

sqrt.of 12 = sqrt of x^2

sqrt of 4.3 = x

2sqrtof 3 = x

Answer 4

remember also that in the third one, you're solving, 12 = x^2, which is a quadratic so there are actually two solutions for this one...

Answer 5

Thanks, it is always late night math with basics that I doubt my ability to do the basics

Answer 6

np

Answer 7

oh yes... so that would be + and - 2sqrt 0f 3... ^_^