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factor completely 6x^4y^3+21x^3y^2-9x^2y
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The common factor in this expression is \[3x^2y\] We get \[3x^2y(2x^2y^2+7xy-9)\]
6x^4y^3+21x^3y^2-9x^2y = 3x^2y (2x^2y^2 +7xy - 3)
Thanks! I am wrong sometimes! Silly me!
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