Question

PLEASE HELP! Given the triangle and equation below, what is the value of x?
(pictures attached)

Answer 1

A

Answer 2

B

Answer 3

C

Answer 4

D

Answer 5

where is the unknown x?

Answer 6

sec∠C - cot∠A = 3x

Answer 7

Hey, I don't see where x in the picture?

Answer 8

the unknown side = \[=\sqrt{7^2 - 6^2} = \sqrt{13}\]

sec∠C = 1/cos∠C = \[= 7/ 6\]
cot∠A = 1/tan∠A = \[= \sqrt{13} / 6\]

sec∠C - cot∠A \[= (7/ 6) - \sqrt{13} / 6\] \[= (7- \sqrt{13} )/ 6\]

sec∠C - cot∠A = 3x
x= 1/3 (sec∠C - cot∠A )
\[=(1/3) [(7- \sqrt{13} )/ 6]\]
\[= [(7- \sqrt{13} )/ 18]\]

Answer 9

@callisto happy to work together again!

Answer 10

@Chlorophyll same here!

Answer 11

Hey, what x they asking? side or angle?

Answer 12

this is all i've been given to answer this question.

Answer 13

sec∠C - cot∠A = 3x
therefore x=( 1/3) (sec∠C - cot∠A )

Answer 14

@pineapple31 i've posted the workings above, please check it and see if you can understand

Answer 15

I'm pretty sure Callisto does pretty good job :)

Answer 16

so the answer is B?

Answer 17

A, i think haven't you check my workings?

Answer 18

I don't even know what x you're asking, how can I answer properly if I don't know what you want (?)

Answer 19

yes!

Answer 20

@chlorophyll
given:
sec∠C - cot∠A = 3x
therefore
x=( 1/3) (sec∠C - cot∠A )