Question

How to find the critical number of f(x)=(x^2-3x+2)^1/2

Answer 1

\[f'(x)=\frac{2x-3}{2\sqrt{x^2-3x+2}}\] is a start

Answer 2

set the numerator equal to zero and solve to find the critical number

Answer 3

why there is 2 in the front?

Answer 4

the derivative of
\[\sqrt{f(x)}\] is
\[\frac{f'(x)}{2\sqrt{f(x)}}\] by the chain rule

Answer 5

correct