Ask your own question, for FREE!
Mathematics 27 Online
OpenStudy (anonymous):

hey who is..?

OpenStudy (angela210793):

I think is....

OpenStudy (anonymous):

thank you Angela

OpenStudy (angela210793):

Glad I could help xD

OpenStudy (anonymous):

can you help me?

OpenStudy (anonymous):

Angela I'm From Iran

OpenStudy (angela210793):

If I can ofc I will :) and if I can't someone else will... What's ur question?

OpenStudy (anonymous):

limx→π/4cos2x÷sinx−cosx

OpenStudy (angela210793):

Hmmmm....I'm sorry I'm not good at limits.....post this question again and surely someone else will help you

OpenStudy (anonymous):

thank you very much angela

OpenStudy (angela210793):

I didn't do anything :S

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!