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Physics 6 Online
OpenStudy (anonymous):

The figure shows the potential energy of a 400g particle as it moves along the x-axis. Suppose the particle's mechanical energy is 12 J. http://i.imgur.com/ojYDr.jpg Where are the particle's turning points? What is the particle's speed when it is at x= 2.0m? What is the particle's maximum speed? At what position or positions does this occur? I've been staring at the graph for an hour and don't really have any clue what to do. I know that turning pt is when K = 0 so I think it's at x = 2 and since U + K = 12 J so turning pt is like 7?

OpenStudy (mani_jha):

Why do you think that the turning point is at x=2? Is K=0 there?

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