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- from this equation how many will be ,,b" ? 1= -2b(lg((x+yb)/(ab))
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could you clarify the question
b= ?
lg is logarithm on base 10
\[\frac{\log(x+by)}{ab} = -\frac{1}{2b}\] \[\log(x+by) = -\frac{a}{2}\] \[x+by = 10^{-a/2}\] \[b = \frac{10^{-a/2}-x}{y}\]
thank you but there is lg( (x+by)/(ab) )
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can you solve it ,help me if there is so ?
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