Question

x^3(sinx+1)

Differentiate!

Answer 1

\[x^3(sinx+1)\]

Answer 2

product rule u = x^3 du = 3x^2
v = sin(x) dv = cos(x)

dy/dx = x^3cos(x) + 3x^2sin(x)

= x^2(xcos(x) + sin(x))

Answer 3

oops v = sin(x) + 1 dv = cos(x)

dy/dx = x^3cos(x) + 3x^2(sin(x)+1)

Answer 4

Thanks :)