Question

(x^2+3x-4)/(x^2+2x-8)*(x^2+7x+10)/(x^2+4x-5)

Just multiplying :P

Answer 1

Factor the trinomial x^(2)+3x-4.
((x+4)(x-1))/(x^(2)+2x-8)*(x^(2)+7x+10)/(x^(2)+4x-5)

factor the trinomial
((x+4)(x-1))/((x+4)(x-2))*(x^(2)+7x+10)/(x^(2)+4x-5)

Reduce the expression by canceling out the common factor of (x+4) from the numerator and denominator.
(x-1)/(x-2)*(x^(2)+7x+10)/(x^(2)+4x-5)

Factor the trinomial x^(2)+7x+10.
(x-1)/(x-2)*((x+5)(x+2))/(x^(2)+4x-5)

factor the trinomial
(x-1)/(x-2)*((x+5)(x+2))/((x+5)(x-1))

reduce the expression by canceling out the common factor of (x+5) from the numerator and denominator.
(x-1)/(x-2)*(1(x+2))/(x-1)

Reduce the expression by canceling out the common factor of (x-1) from the numerator and denominator.
(x+2)/(x-2)

Answer 2

Thank you very much!